What is the simplest radical form of #sqrt116#?

1 Answer
sjc · EZ as pi
Feb 17, 2017

#sqrt116=2sqrt29#

Explanation:

We try and split the number into the product of the factors where at least one of the numbers might be a perfect square.

Start by breaking it as you would for prime factorisation, and continue until you have perfect squares ( if they are there).

#sqrt116=sqrt(2xx58)=sqrt(2xx2xx29#

#sqrt(4xx29)=sqrt4 xxsqrt29#

Find any roots that you can.

#sqrt116=2sqrt29#

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